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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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Markyb978 Markyb978
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7 years ago Edited: 7 years ago, Markyb978
A can of hairspray has a volume of 684 mL and contains 6.43 g of carbon dioxide as the propellant what is the pressure inside the can at 25°C?
Post Merge: 7 years ago

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6 years ago
Using the Ideal Gas Law:

PV=nRT

Calculate the number of moles of CO2:

\(number\ of\ moles\ of\ CO_2=\frac{Mass\ of\ CO_2\ in\ g}{Molar\ Mass\ of\ CO_2\ in\ \frac{g}{mol}}\)

\(CO_2=\ \frac{6.43 g}{44.01\ \frac{g}{mole}}\)

nCO2 = 0.14610315837 mole

R at 25oC = 0.082057338 L . atm/ K . mol

T in K = 25oC + 273 K= 298K.

V in L = 0.684 L

Rearrange:

P = nRT/V
   = [0.14610315837 mole x (0.082057338 L . atm/ K . mol) x 298K ]/ 0.684 L
   = 5.22 atm
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