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zule zule
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11 years ago
For the lab we ran 3 trials titrating an unknown acid with NaOH.  The NaOH was .1 M.  I know the formula for this is Molarity NaOHxVolume NaOH = Molarity Acid x Volume of Acid (which was 25 mL in each one of our trials)  The thing I am confused about is what should I use as my volume of NaOH.  We calculated the equivalance point, the 1/2 equiv point... etc.  Input appreciated!
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wrote...
11 years ago
To find the molarity of the acid the volume of NaOH to use is the volume of NaOH at the endpoint (equivalence point) of the titration.
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