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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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mib123 mib123
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10 years ago
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#1
10 years ago
enantiomeric excess = (amount of R - amount of S) / (amount of R + amount of S).

We have 2 equations and 2 variables:
r + s = 10 (grams)
(r - s)/(r+s) = 0.6
so r - s = 0.6 * (r+s) = 0.6 * 10 = 6
(r+s) + (r-s) = 2r = 10 + 6 ---> r = 8 grams R enantiomer
s = 10 - 8 = 2 grams S enantiomer
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