Top Posters
Since Sunday
5
a
5
k
5
c
5
B
5
l
5
C
4
s
4
a
4
t
4
i
4
r
4
Home Q & A Board Science-Related Homework Help Mathematics
New Topic  
Smilez Smilez
wrote...
Go to Answer
Posts: 18
Rep: 0 0
10 years ago
Phil reported that the receipts from a recent concert totaled $1913.75. Furthermore, he announced that 540 people had attended the concert. Students were charged $2.25 each for admission to the concert, and adults were charged $5.50 each. How many adults and how many children attended the concert?

Variable Definitionl:

Equations:

Solving:
I have the answer, but I need to see your equations.
Read 677 times
7 Replies
Replies
wrote...
#1
10 years ago
there are two unknowns in this problem so we need two independent equations to solve it
let y= number of adults
and x= number of children

so
x + y= 540
and
2.25*x + 5.5*y= 1913.25

hope that helps..
wrote...
#2
10 years ago
s = number of students
a = number of adults

s + a = 540
2.25s + 5.50a = 1913.75

a = 540 - s
2.25s + 5.50(540 - s) = 1913.75
2.25s + 2970 - 5.50s = 1913.75
-3.25s = -1056.25

s = 325
a = 540 - 325 = 215
wrote...
#3
10 years ago
Question is "How many adults and how many children attended the concert?", so A=adults, C=children

2 unknowns, need 2 equations

540 people-> A + C =540
$1913.75 -> 5.50A + 2.25C = 1913.75

One way to solve is A = 540-C, use this in second to get
5.50(540-C)+2.25C=1913.75
5.50*540-5.50C+2.25C=1913.75, etc.
wrote...
#4
10 years ago
Start by asking yourself what the question WANTS.
They want to know "How many adults and how many children attended the concert?"
So pick variables for these two things:

let A = the number of adults who attended the concert
let C = the number of children who attended the concert

Then use these to write two logical equations.
** If you are not used to using TWO variables, you could use A for the number of adults and 540-A for the number of kids.

I'll leave the rest up to you. Try stuff and see if you hit the answer.
wrote...
#5
10 years ago
s+a=540, 2.25s+5.50a=$1913.75, s=540-a, 2.25[540-a]+5.50a=1913.75, 1215-2.25a+5.50a=1913.75, 3.25a=698.75, a=215, s=540-215=325! Answer
Answer accepted by topic starter
tom_andrewstom_andrews
wrote...
#6
Posts: 44
Rep: 0 0
10 years ago
Sign in or Sign up in seconds to unlock everything for free
1

Related Topics

wrote...
#7
10 years ago
For problems with just 2 variables, it would be good to know the two ways of finding the values. Here they are:

- Process of Elimination
- Process of Subsitution


(Impossible to go through Pre-Algebra without knowing these)
New Topic      
Quick Reply
Explore
Post your homework questions and get free online help from our incredible volunteers
  1277 People Browsing
Start New Topic Take the Tour CoursesNew Study Tools Topics Trending Browse by Textbook
Related Images
  
 295
  
 279
  
 266
Your Opinion
Who will win the 2024 president election?
Votes: 3
Closes: November 4
Previous poll results: What's your favorite math subject?