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rini rini
wrote...
Posts: 13
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10 years ago
How do we solve a a system of three equations in three variables? I cannot find an example of how to do it.

20=400a+20b+c

110=1600a+40b+c

295=3600a+60b+c
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3 Replies
Replies
wrote...
10 years ago
Hint:  use cramer's rule.
Answer accepted by topic starter
Michi09Michi09
wrote...
Posts: 26
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10 years ago
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This verified answer contains over 160 words.
1

Related Topics

wrote...
10 years ago
{a =  19/160,

 b  =   -(21/8),

c  = 25}
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