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cloveb cloveb
wrote...
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Posts: 782
6 years ago
A horizontal force of 200 N is applied to a 55-kg cart across a 10-m level surface. If the cart accelerates at 2.0 m/s2, then what is the work done by the force of friction as it acts to retard the motion of the cart?

(1) -900 J (2) -1000 J (3) -1100 J (4) +900 J (5) +1000 J

PHY 2053 Exam
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wrote...
Staff Member
6 years ago
F = ma
a = 200/55 = 3.64m/s^2

so force due to friction = 55(3.64 - 2) = 90N

so work done = -90 * 10 =- 900J

as direction is opposite to force
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