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spammonia spammonia
wrote...
Posts: 31
11 years ago Edited: 11 years ago, spammonia
I am terrible at stoichiometric problems, especially in real life situations. I want someone to check my answer. So I have to make a 25mL solution consisting of 4 different "ingredients" in different amounts, one of them being A. I have a 0.25M stock solution of A made and in the new 25mL solution I was supposed to figure out how many mLs of A I'd need to put in to make the new concentration of A to be 0.025M in the new solution. I got 2.5 mL from my calculations, so am I right?
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wrote...
11 years ago
Quick napkin math but I am getting the same answer.

To figure out how many moles of A you need for your final solution:
(0.025 M)(25mL)(1L/1000mL) = 0.000625 moles of A

Set the moles of A needed equal to the other side:
(0.25 M)(X mL)(1L/1000mL) = 0.000625 moles of A

X = 2.5 mL

congrats =D
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