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majarm majarm
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6 years ago
The local amateur soccer club spent $1640 on tickets to a professional hockey game. If the club bought 2.5 times as many eight-dollar tickets than the number of twelve-dollar tickets and four fewer fifteen-dollar tickets than 7/10 the number of twelve dollar tickets, how many of each type of ticket did the club buy?
Textbook 
Contemporary Business Mathematics with Canadian Applications

Contemporary Business Mathematics with Canadian Applications


Edition: 11th
Authors:
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wrote...
6 years ago
Let the number of $12 tickets be x.
Number of $8 tickets = 2.5x
Number of $15 tickets =  x - 4
Value of the $12 tickets = $12x
Value of the $8 tickets = $8(2.5x)
Value of the $15 tickets = $15( x - 4)
∴   12x + 8(2.5x) + 15 (7/10x - 4) = $1640
   12x + 20x + 10.5x - 60 = 1640
   42.5x = 1700
   x = 40
Sales were 40 $12 tickets, 100 $8 tickets, and 24 $15 tickets.
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