What are the spectator ions in the given balanced chemical equation CaCI2(aq) plus k2CO3(aq) CaCO3 (

The balanced chemical equation looks like this

\[CaCl_(2(aq)) + K_2CO_(3(aq)) \Longrightarrow 2KCl_((aq)) + CaCO_(3(s))\]

The complete ionic equation can be used to see what takes place between the ions present in solution

\(Ca_((aq))^(2+) + 2Cl_((aq))^(-) + 2K_((aq))^(+) + CO_(3(aq))^(2-) \Longrightarrow 2K_((aq))^(+) + 2Cl_((aq))^(-) + CaCO_(3(s))\)

If you eliminate spectator ions, which are ions present on both sides of the reaction, you'll get the net ionic equation

\(Ca_((aq))^(2+) + CO_(3(aq))^(2-) \Longrightarrow CaCO_(3(s))\)

The important thing to notice here is that calcium chloride dissociates in aqueous solution to form

\(CaCl_(2(aq)) \Longrightarrow Ca_((aq))^(2+) + 2Cl_((aq))^(-)\)