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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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!JRon@n !JRon@n
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Posts: 91
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10 years ago
249            .....257
Cf + X .... Rf  +        4  1 n
98              ......104   ........0

(a 4 coefficient is in front of the neutron particle meaning 4 neutrons)
what do I place as X in order to balance the equation?
I thought I had to add 3 alpha particles but apparently that's not it. Please help.
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2 Replies
Replies
wrote...
#1
10 years ago
The key point is that X is one particle, not three.

Your three alpha particles total up to a mass number of 12 and an atomic number of 6.

The one particle that hit the Cf was 6-C-12, the isotope of carbon with mass number 12.
Answer accepted by topic starter
friskiefriskie
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#2
Posts: 21
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10 years ago
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