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elle7nc elle7nc
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10 years ago
determine the mass of potassium carbonate needed to fully precipitate all the calcium from a 25 mL sample of 15% calcium chloride solution.  How do I do this or what other information do I need.  There is a note: this is the same concentration as the solution you used in the first experiment.  Please help.
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Staff Member
Educator
10 years ago
K2CO3 + CaCl2 -----> CaCO3 + 2 KCl


15 g of CaCl2

moles = 15/111 = 0.135


15 g of K2CO3


moles = 15/138.2 = 0.1085


Limiting reagent = K2CO3
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