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Home Q & A Board Science-Related Homework Help High School Level Science
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EA EA
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10 years ago
 In a randomly mating population of mice, 25.0 of every 100.0 mice born have white fur, a recessive trait.
a) calculate the frequency of each allele in the population
b) Calculate the genotype frequencies for the population
 
ive seen an  answer of this in another thread already, but could someone answer it according to question a and b separately . and use the equations p+q=1 and p^2+2pq+q^2=1.00. and please explain
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#1
Staff Member
Educator
10 years ago
Fr(white) = fr(bb) = 0.25, so fr(b) = sqrt(0.25) = 0.5; therefore, fr(B) = 1-0.5 = 0.5.
Mastering in Nutritional Biology
Tralalalala Slight Smile
EA Author
wrote...
#2
10 years ago
Quote from: padre (10 years ago)
Fr(white) = fr(bb) = 0.25, so fr(b) = sqrt(0.25) = 0.5; therefore, fr(B) = 1-0.5 = 0.5.
thnks padre, but did u see what i wrote under the q?
wrote...
#3
Staff Member
Educator
10 years ago
HI

Quote from: EA (10 years ago)
a) calculate the frequency of each allele in the population

Frequency of big B is 50%, small b is 50%.

Quote from: EA (10 years ago)
b) Calculate the genotype frequencies for the population

25% will be bb
2pq (2*0.5*0.5 = 0.5), 50% will be Bb
and 25% will be BB
Mastering in Nutritional Biology
Tralalalala Slight Smile
EA Author
wrote...
#4
10 years ago
could you pleeeeease explain this Slight Smile?
Post Merge: 10 years ago

Quote from: padre (10 years ago)
HI

Quote from: EA (10 years ago)
a) calculate the frequency of each allele in the population

Frequency of big B is 50%, small b is 50%.

Quote from: EA (10 years ago)
b) Calculate the genotype frequencies for the population

25% will be bb
2pq (2*0.5*0.5 = 0.5), 50% will be Bb
and 25% will be BB
could you pleeeease explain this Slight Smile?
wrote...
#5
Staff Member
Educator
10 years ago
You're killing me EA!

Wink Face

25.0 of every 100.0 ..... divide the two numbers 0.25 or 25% have bb (the recessive genotype)

Use p^2+2pq+q^2=1.00

let p be the dominant allele, q the recessive

q^2 = 0.25, solve for q by square rooting both side. You get 0.50. Now you have your q, or the prevalence of this allele (b) in the whole population. Then you use p + q = 1 to find the prevalence of B by solving for p. Once you have both p and q, use 2pq to find the heterozygous genotype.
Mastering in Nutritional Biology
Tralalalala Slight Smile
EA Author
wrote...
#6
10 years ago
Quote from: padre (10 years ago)
You're killing me EA!

Wink Face

25.0 of every 100.0 ..... divide the two numbers 0.25 or 25% have bb (the recessive genotype)

Use p^2+2pq+q^2=1.00

let p be the dominant allele, q the recessive

q^2 = 0.25, solve for q by square rooting both side. You get 0.50. Now you have your q, or the prevalence of this allele (b) in the whole population. Then you use p + q = 1 to find the prevalence of B by solving for p. Once you have both p and q, use 2pq to find the heterozygous genotype.
thank you so much padre! Wink Face
wrote...
#7
Staff Member
Educator
10 years ago
NP

Please mark as solved.
Mastering in Nutritional Biology
Tralalalala Slight Smile
wrote...
#8
On Hiatus
10 years ago
thank you guys
Machiavelli
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