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12 years ago
A boy jumps at a speed of 20.0 m/s at an angle of 25.0° above the horizontal. What is the horizontal component of the boy's velocity?
A) 18.1 m/s
B) 15.6 m/s
C) 8.45 m/s
D) 12.6 m/s
E) 9.33 m/s
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#1
Valued Member
12 years ago
Vx = (20 m/s)*cos(25)
 Vy = (20 m/s)*sin(25)

18.1 is the answer
I don't feel like riding until everything blurs.

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#2
12 years ago
Yes, should be A
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