Find the molarity of the solution at 298 K

Answer:

osmotic pressure, π = iMRT (i = van't hoff factor , M = Molarity)

i for glucose = 1,

π = MRT

M = π/RT

= 125/0.082*298

= 5.11

therefore, molarity of solution, = 5.11


Answer:

? = i * M * R * T, where i is the van't Hoff factor (i = 1 for glucose), M is the molarity, R is the ideal gas constant with a value of 0.0821 L*atm/mol*K, and T is the temperature in K

? = (1) * (M) * (0.0821 L*atm/mol*K) * (298 K)
48.9 atm = (1) * (M) * (0.0821 L*atm/mol*K) * (298 K)
M = 1.998 M is the answer.


Answer:

osmotic pressure = MRT
83.1atm = M x 0.0821L-atm/mole-K x 298K
M = 3.40M

Thank you!