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gh1991 gh1991
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Posts: 108
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12 years ago
A cat drops from a shelf 3.9 ft above the floor and lands on all four feet. His legs bring him to a stop in a distance of 12 cm.

Part A:
Calculate his speed when he first touches the floor (ignore air resistance). Express your answer to two significant figures and include the appropriate units.

Part B:
Calculate how long it takes him to stop. Express your answer to two significant figures and include the appropriate units.

Part C:
Calculate his acceleration (assumed constant) while he is stopping, in m/s^2. Express your answer to two significant figures and include the appropriate units.

Part D:
Calculate his acceleration (assumed constant) while he is stopping, in g's. Express your answer to two significant figures.
Calculate
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wrote...
Valued Member
12 years ago
You have to convert 3.6 ft into meters first, otherwise you'd follow these steps Face with Rolling Eyes

a) vf^2=v0^2+2ad

vf^2=0+2gh or vf= sqrt[2gh]= sqrt[2*9.8m/s/s*3.6m] = 8.4m/s

b) once he hits the floor, his speed goes from 8.4m/s to 0, meaning the avg velocity is 4.2m/s

therefore time = dist/avg speed = 0.12m/4.2m/s

c) accel = - 8.4m/s / time that you just calculated

d) divide the accel you just obtained by 9.8m/s/s / g
Sunshine ☀ ☼
wrote...
Staff Member
12 years ago
gh1991, welcome to the forum, see how I answered this... Colleen is right, almost Wink Face

https://biology-forums.com/index.php/topic,13966/new.html#new
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