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zzz1090 zzz1090
wrote...
Posts: 204
Rep: 1 0
12 years ago
A 70 kW single-phase load with a power factor of 0.74 lagging is fed by a long cable with an impedance of 0.007+j0.005 ? per phase. The voltage across the load is 230 V RMS. Calculate the heat loss in the cable in Watt [W].
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wrote...
12 years ago
Basically the heat losses = I^2 * R
we need to calculate the current I drawn by the load
I = P / ( V * P.f ) where
I is the current demand in Amperes
P the power demand of the load in watts
V voltage across the load on volts
p.F power factor

I = 70,000 / ( 230 * 0.74 ) = 411.28 A  
Heat loss = I ^2 * R
Heat losses = (411.28)^2 * 0.007 = 1184.06 W

Hope I helped
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