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nypr1nc355 nypr1nc355
wrote...
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12 years ago
at a pressure of 750 mm Hg and a temperature of 298 K.

What is the percent chlorine (by mass) in the unknown chlorofluorocarbon?
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wrote...
12 years ago
use the ideal gas law to find the number of moles of CL2.
(.987)(.583)=x(.0821)(298)
.575421=24.4658x
.0235 mol=x
convert moles Cl2 to grams.
.0235 mol/1 mol=x g/35.45 g
x=.833
divide that answer by 2.95 to get .2823
multiply by 100 to get 28.23% Cl.
There was 28.23% Cl in the CFC.
wrote...
12 years ago
Let the chlorofluorocarbon be called CFC. Atomic weights: Cl=35.5  Cl2=71

583mLCl2/2.95gCFC x 750mmHg/760mmHg x 273K/298K x 1molCl2/22,400mLCl2 x 71gCl2/1molCl2 x 100% = 56.6% Cl
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