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centimetergrove centimetergrove
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Posts: 10
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10 years ago
This problem has me confused for a month now. Please help?!

In cats, curled ears (Cu) results from an allele that is dominant over an allele for normal ears (cu). Black color results from an independently assorting allele (G) that is dominant over an allele for gray (g). A gray cat homozygous for curled ears is mated to a homozygous black cat with normal ears. All the F1 cats are black and have curly ears.

(a)   If two of the F1 cats mate, what phenotypes and proportions are expected in the F2?
   If F1 cats mated, GgCucu × GgCucu, then following proportions and phenotypes are expected in the F2:
      9/16 Black with curly ears
      3/16 Black with normal ears
      3/16 Gray with curly ears
      1/16 Gray with normal ears

(b)   An F1 cat mates with a stray cat that is gray and possesses normal ears. What phenotypes and proportions of progeny are expected from this cross?
   The mating of a F1 cat (GgCucu) with a gray cat with normal ears (ggcucu) is a testcross in which we would expect to produce equal numbers of all the different progeny classes:
      ¼ Black with curly ears
      ¼ Black with normal ears
      ¼ Gray with curly ears
      ¼ Gray with normal ears

My question is what does the punnet square look like for part (a) and part (b) ?
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Staff Member
Educator
10 years ago
HI

Hope this helps
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Mastering in Nutritional Biology
Tralalalala Slight Smile
wrote...
10 years ago
HI

Hope this helps
hello, sory this does not help, the problem is already solved and i know they did a punnet square to obtain the 9-3-3-1 ration but i just dont understand what the punnet square is supposed to look like, same for the test cross in part (b) ?!
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