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fosmanali01 fosmanali01
wrote...
Posts: 78
9 years ago
Solve for n in the equation:

nP3 = 2(nC4)

1st step :  n! / (n-3)! = 2 ( n! / (n-4)! 4!)

2nd step : ?
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wrote...
Staff Member
9 years ago
nP3 = 2(nC4)
n! / (n-3)! = 2 n! / [(n-4)! 4!]
4! n! = 2 n! (n-3)! / (n-4)!
12 = (n-3)! / (n-4)! = n - 3
n = 15
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