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fosmanali01 fosmanali01
wrote...
Posts: 78
9 years ago
.Given sinθ=0.6293 where 900≤θ≤1800, determine the smallest positive angle that is co-terminal to θ and is not equal to θ.
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wrote...
9 years ago
so here as sin\({\theta}\) is = 0.6293

\({\theta}\) = arc sin (0.6293) = 38.9984

but as we need it to be in second quadrant it is 90+38.9984 = 128.9984 degrees
wrote...
Educator
9 years ago
but as we need it to be in second quadrant it is 90+38.9984 = 128.9984 degrees

Why does it need to be in the second quadrant?
wrote...
9 years ago
Its becoz theta is said to be in between 90 and 180 degrees which indirectly says that it should be in Q2
wrote...
Educator
9 years ago
where 900≤θ≤1800

Okay, but then how do you rationalize this, what does this mean?
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