× Didn't find what you were looking for? Ask a question
Top Posters
Since Sunday
w
5
a
3
j
2
a
2
t
2
u
2
r
2
j
2
j
2
l
2
d
2
y
2
Home Q & A Board Biology-Related Homework Help Biochemistry
New Topic  
mdlc0516 mdlc0516
wrote...
Go to Answer
Posts: 657
Rep: 0 0
6 years ago
The phosphorylation of fructose 6-phosphate to fructose-1,6-bisphosphate is the committed step in glycolysis because
 a. it is the rate-limiting step.
  b. it is the most strongly exergonic step in the pathway.
  c. fructose 1,6-bisphosphate can undergo no other reactions than those of glycolysis.
  d. two phosphate groups are involved.
Read 64 times
1 Reply
Replies
Answer verified by a subject expert
ABascombABascomb
wrote...
#1
Posts: 358
Rep: 0 0
6 years ago
Sign in or Sign up in seconds to unlock everything for free
1

Related Topics

mdlc0516 Author
wrote...

6 years ago
This calls for a celebration Person Raising Both Hands in Celebration
MAry1395
wrote...

Yesterday
Thanks
Starfiew
wrote...

2 hours ago
This helped my grade so much Perfect
New Topic      
Quick Reply
Explore
Post your homework questions and get free online help from our incredible volunteers
  1248 People Browsing
Start New Topic Take the Tour CoursesNew Study Tools Topics Trending Browse by Textbook
Live Chat
Related Images
  
 2422
  
 233
  
 379
Your Opinion
Who will win the 2024 president election?
Votes: 119
Closes: November 4
Previous poll results: Who's your favorite biologist?