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msflygirl msflygirl
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Posts: 1
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9 years ago
Suppose that the probability that a new medication will cause a bad side effect is 0.03. If this medication is given to 150 people, what is the probability that exactly three of them will experience a bad side effect?
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wrote...
Staff Member
9 years ago
Suppose that the probability that a new medication will cause a bad side effect is 0.03. If this medication is given to 150 people, what is the probability that more than three of them will experience a bad side effect? Round answer to 4 decimal places.

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You should have or you need a cumulative binomial chart or a calculators
with a Stat function.
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Your problem:
Binomial with n = 150, p = 0.03, 4 <= x <= 150

 
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Your problem:
P(4 <= x <= 150) = 1 - P(0 <= x <= 3)
= 1 - [P(x= 0) + P(x=1) + P(x=2) + P(x=3)]
= 1 - [0.01037 + 0.048106..+ 0.110843 + 0.16912...)
= 1 - [0.33844
= 0.66156...

150nCr0(.03)^0(.97)^(150) = .0104

150nCr1(.03)^1(.97)^(149) = .0481

150nCr2(.03)^2(.97)^(148) = .1108

150nCr3(.03)^3(.97)^(147) = .1691

P(0) + P(1) + P(2) + P(3) = .0104 + .0481 + .1108 + .1691 = .3384

1 - (P(0) + P(1) + P(2) + P(3)) = 1 - .3384 = .6616 = 66.16%

66.16% <==ANSWER for the probability that more than three of them will experience a bad side effect
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Answer accepted by topic starter
metal_zeldametal_zelda
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9 years ago Edited: 9 years ago, metal_zelda
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This verified answer contains over 760 words.
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