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OldSpice OldSpice
wrote...
Posts: 6432
9 years ago
Given that 50.0 mL of 0.125 M Hg(NO3)2 reacts completely with 0.145 M NaI, what volume of sodium iodide is required?
   Hg(NO3)2(aq) + NaI(aq) ? HgI2(s) + NaNO3(aq)
A) 21.6 mL
B) 29.0 mL
C) 43.1 mL
D) 58.0 mL
E) 86.2 mL
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Answer accepted by topic starter
ElectricElectric
wrote...
Top Poster
Posts: 6431
9 years ago
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.silent.boss

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OldSpice Author
wrote...
9 years ago
Perfect!

..Thank you so much for your support
wrote...
9 years ago
My pleasure
.silent.boss
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