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emilyliv emilyliv
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3 years ago
How many terms are there in the following sequence:  8,32,128,...96757023244288
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#1
Educator
3 years ago
Watch this:



Ok, so for this, determine what kind of sequence it is. Looks to me like geometric because there's a common ratio of 4.

32/8 = 4
128/32 = 4

From the video, the general equation is an = a1rn-1

We have:

96757023244288 = (8)(4)n-1

Solve for n:

96757023244288 / 8 = (4)n-1

log (96757023244288 / 8) = log[(4)n-1]

log (96757023244288 / 8) = (n-1)log(4)

log (96757023244288 / 8) / log(4) = n - 1

log (96757023244288 / 8) / log(4) + 1 = n

n = 22.72

22 terms, is that one of the options?
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