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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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jcp_03 jcp_03
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3 years ago
In order to determine the identity of a particular lanthanide metal (M), a voltaic cell is constructed at 25°C with the anode consisting of the lanthanide metal as the electrode immersed in a solution of 0.0594 M MCl3, and the cathode consisting of a copper electrode immersed in a 1.00 M Cu(NO3)2 solution. The two half-reactions are as follows:
M(s) → M3+(aq) + 3e–
Cu2+(aq) + 2e–→ Cu(s)
The potential measured across the cell is 2.64 V. What is the identity of the metal?
Reduction Half-Reaction
E° (V)
Cu2+(aq) + 2e–→ Cu(s)
0.34
Ce3+(aq) + 3e–→ Ce(s)
–2.336
Dy3+(aq) + 3e–→ Dy(s)
–2.295
Eu3+(aq) + 3e–→ Eu(s)
–1.991
Gd3+(aq) + 3e–→ Gd(s)
–2.279
Sm3+(aq) + 3e–→ Sm(s)
–2.304
 



▸ Ce

▸ Eu

▸ Dy

▸ Gd

▸ Sm
Textbook 
Chemistry: An Atoms First Approach

Chemistry: An Atoms First Approach


Edition: 3rd
Authors:
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Bowmanette35Bowmanette35
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