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mlhickey mlhickey
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3 years ago
Determine the enthalpy change in the following equation:

Cl2(g) + H2O(l) → 2 HCl(g) + 1/2 O2(g)
Δf H2O(l) = -285.8 kJ/mol
Δf HCl(g) = -92.31 kJ/mol


▸ 193.5 kJ/mol

▸ -470.4 kJ/mol

▸ 470.4 kJ/mol

▸ 101.2 kJ/mol

▸ -101.2 kJ/mol
Textbook 
General Chemistry: Principles and Modern Applications

General Chemistry: Principles and Modern Applications


Edition: 11th
Authors:
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ethom947ethom947
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3 years ago
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wrote...
2 years ago
Determine the enthalpy change in the following equation:
2/3 H2S(g) + O2(g) → 2/3 SO2(g) + 2/3 H2O(l)
Given:
ΔH°f H2O(l) = -285.8 kJ/mol
ΔH°f H2S(g) = -20.63 kJ/mol
ΔH°f SO2(g) = -296.8 kJ/mol
wrote...
2 years ago
Determine the enthalpy change in the following equation: 2/3 H2S(g) + O2(g) → 2/3 SO2(g) + 2/3 H2O(l) Given: ΔH°f H2O(l) = -285.8 kJ/mol ΔH°f H2S(g) = -20.63 kJ/mol ΔH°f SO2(g) = -296.8 kJ/mol
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