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wheels123 wheels123
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3 years ago
When [Ni(NH3)4]2+ is treated with concentrated HCl(aq), two compounds having the same formula, [Ni(NH3)4Cl2], designated I and II, are formed. Compound I can be converted to compound II by boiling it in dilute HCl(aq). A solution of I reacts with oxalic acid, H2C2O4, to form [Ni(NH3)4(C2O4)]. Compound II does not react with oxalic acid. Compound II is:

▸ the cis isomer

▸ tetrahedral in shape

▸ the trans isomer

▸ the same as compound I

▸ octahedral in shape
Textbook 
General Chemistry: Principles and Modern Applications

General Chemistry: Principles and Modern Applications


Edition: 11th
Authors:
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derya1234derya1234
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wheels123 Author
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3 years ago
Good timing, thanks!
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this is exactly what I needed
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You make an excellent tutor!
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