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# A 0.500 kg object is thrown vertically upward with an average applied force of 8.20 N by a student. ...

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A week ago
 A 0.500 kg object is thrown vertically upward with an average applied force of 8.20 N by a student. ... 9. A 0.500 kg object is thrown vertically upward with an average applied force of 8.20 N by a student. The force is applied through a displacement of 1.50 m.a. What is the average net force acting on the object?b. What is the velocity of the object when it leaves the student’s hand? (Assume initial velocity is zero)This is the question and I have to use the grasp method. I'm not sure how to clearly find the answer if it is possible for a step-by-step solution, that would be great, have a good one! Read 127 times 4 Replies

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Educator
A week ago
 Let me know if you don't understand the process.Best of luck!
Answer rejected by topic starter
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A week ago Edited: A week ago, s.h_math
 Hi, why is a not the answer to a?Post Merge: A week agoI read it wrong,Post Merge: A week agoIs the direction for Fnet up or down? is the direction for acceleration up?thanks Post Merge: A week agoIn the answer sheet for b, it says the answer is 4.45 m/s
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Educator
A week ago
 Quote from: s.h_math (A week ago)In the answer sheet for b, it says the answer is 4.45 m/sYou're right I forgot to upload the rest of the answer:So, Fg is going down, it should be negative (-4.90). When we combine Fapp with -4.90, we get Fnet:Fnet = 8.20 + (-4.90) = 3.30 N. 3.30 N is positive.Does that make more sense?
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A week ago
 Yes it definitely did, thanks a lot!