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Annonn Annonn
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2 years ago
Consider the following electrochemical reaction:
2Al(s) + 3Zn2+(aq) → 2Al3+(aq) + 3Zn(s)           E° = +0.90 V
What will be the cell potential for this reaction when [Zn2+] = 0.500 M and [Al3+] = 0.0200 M?

+0.88 V

+0.75 V

+1.05 V

+0.92 V

+0.83 V
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Educator
2 years ago
+0.92 V

Use the Nernst equation

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