Top Posters
Since Sunday
e
5
e
4
4
d
4
o
3
p
3
t
3
3
m
3
p
3
m
3
f
3
New Topic  
Anthonyling Anthonyling
wrote...
Posts: 135
Rep: 0 0
A year ago
The chi-square test for independence makes use of the fact that the probability of the intersection of two independent events denoted A and B [i.e.,\(\style{font-family:Times New Roman;}{P(A\cap B)}\)] is:


the sum of the probability of each event:\(\style{font-family:Times New Roman;}{P\left(A\right)+P(B)}\).



the quotient of the probability of event A divided by B:\(\style{font-family:Times New Roman;}{P(A)/P(B)}\).



the product of the probability of each event:\(\style{font-family:Times New Roman;}{P\left(A\right)\ast P(B)}\).



the difference of the probability of the events:\(\style{font-family:Times New Roman;}{P\left(A\right)-P\left(B\right)}\).

Textbook 
Introductory Statistics: A Problem-Solving Approach

Introductory Statistics: A Problem-Solving Approach


Edition: 3rd
Author:
Read 41 times
1 Reply
Replies
Answer verified by a subject expert
overlandtrailoverlandtrail
wrote...
Posts: 159
Rep: 0 0
A year ago
Sign in or Sign up in seconds to unlock everything for free
More solutions for this book are available here
1

Related Topics

Anthonyling Author
wrote...

A year ago
this is exactly what I needed
wrote...

Yesterday
This site is awesome
wrote...

2 hours ago
Thanks
New Topic      
Explore
Post your homework questions and get free online help from our incredible volunteers
  982 People Browsing
Related Images
  
 182
  
 1018
  
 2761