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Anthonyling Anthonyling
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The chi-square test for independence makes use of the fact that the probability of the intersection of two independent events denoted A and B [i.e.,\(\style{font-family:Times New Roman;}{P(A\cap B)}\)] is:


the sum of the probability of each event:\(\style{font-family:Times New Roman;}{P\left(A\right)+P(B)}\).



the quotient of the probability of event A divided by B:\(\style{font-family:Times New Roman;}{P(A)/P(B)}\).



the product of the probability of each event:\(\style{font-family:Times New Roman;}{P\left(A\right)\ast P(B)}\).



the difference of the probability of the events:\(\style{font-family:Times New Roman;}{P\left(A\right)-P\left(B\right)}\).

Textbook 
Introductory Statistics: A Problem-Solving Approach

Introductory Statistics: A Problem-Solving Approach


Edition: 3rd
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overlandtrailoverlandtrail
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