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i_love_science i_love_science
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A year ago
A woman with an abnormally long chromosome 13 (and a normal homolog of chromosome 13) has children with a man with an abnormally short chromosome 11 (and a normal homolog of chro- mosome 11). The probability of producing an offspring that will have both a long chromosome 13 and a short chromosome 11 is 1/4. If such a child is produced, what is the probability that this child will eventually pass both abnormal chromosomes to one of his or her offspring?

The correct answer is that this probability is 25% because that child had a 1/2 chance of passing either chromosome (1/2 x 1/2 = 1/4).

Why is the genotype of the person that the child that is mating with not considered? (What if this person also has abnormal long or short chromosomes?)

Thanks.
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AnonymousAnonymous
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A year ago
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