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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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salonijainnn salonijainnn
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5 months ago

Calcium-39 undergoes positron decay. Each positron carries 5.49 MeV of energy. How much energy will be emitted when 0.00250 mol of calcium-39 decays? (1 MeV = 1.602 × 10–13 J)



▸ 13.2 kJ

▸

1.32 × 104 kJ



▸

1.32 × 106 kJ



▸

1.32 × 109 kJ



▸ None of these choices is correct.
Textbook 
Chemistry: Atoms First

Chemistry: Atoms First


Edition: 4th
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starikovsstarikovs
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