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Calcium-39 undergoes positron decay. Each positron carries 5.49 MeV of energy. How much energy will ...

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Calcium-39 undergoes positron decay. Each positron carries 5.49 MeV of energy. How much energy will ...

Calcium-39 undergoes positron decay. Each positron carries 5.49 MeV of energy. How much energy will be emitted when 0.00250 mol of calcium-39 decays? (1 MeV = 1.602 × 10^–13 J)

▸ 13.2 kJ

▸

1.32 × 10⁴ kJ

▸

1.32 × 10⁶ kJ

▸

1.32 × 10⁹ kJ

▸ None of these choices is correct.

Textbook

Chemistry: Atoms First

Edition: 4^th

Author: Burdge

Read 36 times

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