In general in life I like people who have solutions not problems. So I will propose a solution that I thought of. Please provide feedback.
Hydrogen's oxidation number is 0 when bonded with another hydrogen.
Hydrogen's oxidation number is +1
often when bonded with another molecule in biochemistry.
When two hydrogen's are removed from their parent molecule and they recombine they are going from an oxidation number of +1 to 0. The hydrogen's have been reduced. This means that the parent molecules have been oxidized, respectively.
The extracellular space is considered an oxidizing environment.
Why?
I stated that the extracellular space is more basic (higher pH).
For the parent molecule proton hosting molecule to be oxidized. The hydrogen must be reduced.
This process is called
deprotonation. Where is deprotonation most likely to occur? An environment with a higher pH. The extracellular space is able to reduce the hydrogen, causing the parent molecule to be oxidized. Thus accomplishing oxidation of the larger molecule.
Similar logic can be applied to the intracellular space regarding it being a reducing environment.
What do you think internet world. I have taken no biochemistry in college.
any opinions on what Ca stands for at:
https://www.bio.cmu.edu/courses/03231/LecF04/Lec05/aa_titration.pdfit is attached to the amino acids.
What does Ca stand for in this amino acid picture, I don't think its circa or ..
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