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Parik Parik
wrote...
Posts: 22
Rep: 1 0
9 years ago
19.   Simplify:
a)   23! /20!
b)   (n=2)! /(n+2)n!
c)   Solve for n:
(n+2)!/(n)! = 110

20.   How many different five-digit numbers can be formed from the set of seven numbers {1,2,3,4,5,6,7} if
a)   Repetition is allowed?
b)   Repetition is not allowed
c)   Repetition is allowed and the third digit must be different from the second digit?
Show your calculations!

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wrote...
9 years ago
20.   How many different five-digit numbers can be formed from the set of seven numbers {1,2,3,4,5,6,7} if
a)   Repetition is allowed?
b)   Repetition is not allowed
c)   Repetition is allowed and the third digit must be different from the second digit?
Show your calculations!

How many different five-digit numbers can be formed from the set of seven numbers (1,2,3,4,5,6,7) if repetition is allowed and the third digit must be different from the second digit?

ANS: 7*7*6*7*7
wrote...
9 years ago
c)   Solve for n:
(n+2)!/(n)! = 110

c) (n+2)!/(n)! = 110 (n)!(n+1)(n+2)/(n)! = 110 (n+1)(n+2) = 110 n^2+3n+2 = 110 n^2+3n-108 = 0 (n+12)(n-9) = 0 n = -12, 9

Quote
b)   (n=2)! /(n+2)n!

(n+2)!/(n+2)n! = [(n+2)(n+1)!/(n+2)]/n! = (n+1)!/n! = n+1

Quote
23!/20!

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