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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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swigidy swigidy
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9 years ago
 Can anybody help answer a few questions for me? one of which is
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9 years ago
Similar Question
What is the mass of aluminum metal that reacts to give 11.1 g of manganese metal?
__MnO2(l) + __Al(l) Δ---> __Mn(l) + __Al2O3(l)

3MnO2 + 4Al = > 3Mn + 2Al2O3

moles of Mn metal = 11.1 / 55 = 0.202 moles

this came from the reaction of MnO2 with .202 x 4 / 3 moles of Al = 0.269moles

mass of Al = 0.269 x 27= 7.26g
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