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Whelan Whelan
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10 years ago
Consider the following standard reduction potentials,

   Zn2+(aq) + 2 e- → Zn(s)   E° = -0.76 V
   I2(s) + 2 e- → 2 I-(aq)   E° = +0.54 V

Under standard conditions,
A) Zn2+(aq) is a stronger oxidizing agent than I2(s) and I-(aq) is a stronger reducing agent than Zn(s).
B) I2(s) is a stronger oxidizing agent than Zn2+(aq) and Zn(s) is a stronger reducing agent than I-(aq).
C) Zn(s) is a stronger oxidizing agent than I-(aq) and Zn2+(aq) is a stronger reducing agent than I2(s).
D) I-(aq) is a stronger oxidizing agent than Zn(s) and I2(s) is a stronger reducing agent than Zn2+(aq).
Textbook 
Introductory Chemistry Essentials

Introductory Chemistry Essentials


Edition: 5th
Author:
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hbutler2hbutler2
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