× Didn't find what you were looking for? Ask a question
Top Posters
Since Sunday
5
a
5
k
5
c
5
B
5
l
5
C
4
s
4
a
4
t
4
i
4
r
4
New Topic  
dashylia dashylia
wrote...
Posts: 65
Rep: 0 0
11 years ago
A 1500 kg car experiences a net force of 1100 N force. It accelerates for 10.0 sec from rest.
What is its final velocity after acceleration?
How far does it travel during its acceleration?
Can you explain how to solve these problems?
Read 293 times
2 Replies

Related Topics

Replies
wrote...
11 years ago
Neglecting friction, we will start where most physics problems start: Force = mass * acceleration

First find the acceleration

F = ma

1100=1500a
a= 0.733 m/s^2

Now we will find the distance traveled

vf = vi + at  where vf is the final velocity, vi is the initial velocity, t is time and a is acceleration

vf = 0 + (0.0733)(10.0)

vf= 7.33 m/s

Now we will find the distance traveled

vf^2 = vi^2 + 2ad

(7.33)^2 = 0^2 + 2(0.733)d

d=36.7 m
wrote...
11 years ago
given:

F=1100N        (net force)
W= 1500 kg   (weight)
T=10s             (time)
Vi=0m/s         (velocity from rest)
find Vf (final velocity) and D (the distance traveled)

to start off, we must get the mass of the car, from the formula w=mg (weight is equal to mass x gravity), m = 153.06 N. Then, using the formula F=mA (where A is the acceleration) to get the acceleration, which is A= 7.19 m/s^2.
Then, to calculate the Vf, from the formula A=(Vf-Vi) / T , deriving, Vf=AT+Vi, Vf = 71.9 m/s.
Then for the distance traveled, D=(Vf-Vi) x T, D = 719m.

Summary of answers:
Vf=71.9m/s
D=719m.

not sure though, lol.
New Topic      
Explore
Post your homework questions and get free online help from our incredible volunteers
  1262 People Browsing
Related Images
  
 341
  
 252
  
 329
Your Opinion
What's your favorite funny biology word?
Votes: 328