What were the genotypes of the parents?

1 parent is bn+/bn and ct+/ct
The other is bn+/bn and ct/ct

When you look at the progeny, 30 of them have the dominant trait for eye color and 10 have the recessive trait for eye color.  That's characteristic of a Punnet cross of 2 heterozygous parents.  

For the wings, your ratio is 21 to 19, which is basically 50/50, wich is characteristic of a Punnett cross of a heterozygote with a homozygotic recessive.  

If you make 2 Punnett Squares, one for each trait, you'll see that these traits line up.  If you combine them for both traits, it should also line up.

It's important sometimes to look at each trait separately in order to see the trend.

One parent with normal wings was bn+/bn (or Aa if you prefer) and ct+/ct (or Bb if you prefer)
The parent with cut wings is bn+/bn (or Aa) and ct/ct (or bb if its easier)
This way, the AaxAa cross gives 1/4 progeny that are AA and  1/2 progeny that are Aa having the dominant dull red eye allele.  Also, 1/4 will be aa having brown eyes.
For the wings, the Bbxbb cross gives 1/2 Bb with normal wings and 1/2 bb with cut wings.  For each genotype, multiply the fractions together.  For example, brown eyes with cut wings is 1/4 times 1/2 giving 1/8.  This holds true since the problem says five of 40 (or 1/8) have this phenotype.  Remember, those with AA and Aa have the same eye color so the categories must be added together (AABb is 1/8 at 5 and AaBb is 1/4 at 10).  Here, you get 15, but remember mendelian frequencies are an ideal, not the truth so 16 is possible instead of 15.  Its about ratios rather than exact numbers