Top Posters
Since Sunday
r
4
L
4
3
d
3
M
3
l
3
V
3
s
3
d
3
a
3
g
3
j
3
Home Q & A Board Science-Related Homework Help Mathematics
New Topic  
onestep onestep
wrote...
Go to Answer
Posts: 4
Rep: 0 0
12 years ago
I have 2 equations that I need to solve using the square root property. 2x^2-5=93 and (x+4)^2=81 and I need to explain how I got the answers.  How would I do this?
Read 859 times
2 Replies
Replies
Answer accepted by topic starter
ilindsey05ilindsey05
wrote...
#1
Posts: 66
Rep: 0 0
12 years ago
Sign in or Sign up in seconds to unlock everything for free
This verified answer contains over 160 words.
1

Related Topics

wrote...
#2
12 years ago
quadratic equation
2x^2 - 5x - 93 = 0
x = [ 5 +- sqr(25 - 4(2)(93) ) ] /4
x = - 5.68271 . . . .  and . . . x  = 8.18271

(x+4)^2 = 81
x^2 + 8x - 65 = 0
x =[ -8 +-sqr(64+ 4(65)) ] / 2
x = - 13 .  .  .  . .  . and . . . x = 5
New Topic      
Quick Reply
Explore
Post your homework questions and get free online help from our incredible volunteers
  1480 People Browsing
Start New Topic Take the Tour CoursesNew Study Tools Topics Trending Browse by Textbook
Live Chat
Related Images
  
 11807
  
 400
  
 279