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Home Q & A Board Science-Related Homework Help Mathematics
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julies julies
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11 years ago
Can you help explain how to do this math problem?

Find 4 consecutive even integers such that the sum of the second and fourth is 76.
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4 Replies
Replies
wrote...
#1
11 years ago
The four integers will be
n, n + 2, n + 4, and n + 6
Since the sum of the second and
fourth is 76,
(n + 2) + (n + 6) = 76
2n + 8 = 76
Divide boh sides by 2 to get
n + 4 = 38
So n = 34 and the integer set is
34, 36, 38, and 40. Note that the
second (36) and the fourth (40)
add up to 76.
wrote...
#2
11 years ago
Four consecutive even integers: (2n-2),(2n),(2n+2),(2n+4)

... (2n) + (2n+4) = 76
or 4n + 4 = 76
or n = 72 / 4 = 18

So your four even integers are: 34, 36, 38, 40
wrote...
#3
11 years ago
x + (x + 2) + (X + 4) +(x + 6)
x + 2 + x + 6 = 76
2x + 8 = 76
2x = 76 - 8
2x = 68
x = 34
Numbers are 34,36,38 and 40
Answer accepted by topic starter
buffnstuffbuffnstuff
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#4
Posts: 85
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11 years ago
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