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oaqadir oaqadir
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Posts: 59
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11 years ago
Can anyone help me with these two questions?

1a. Explain how you can find the equation of a line when you know the coordinates of the two points on the line.

1b. Solve the equation: 5-11
                                  x+2=3  (both equations are equal to 3)

Use any method. Use another method to check your soloution.
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wrote...
11 years ago
1a. You can find the equation of a line with two given points on the line with slope-intercept form (y=mx+b). You just need to find the slope(m) and the y-intercept(b).  First, you find the slope (m) using the two given coordinate points. Find the difference between the y variable of the first coordinate, from the y variable of the second coordinate.  Divide this number by the difference between the x variable of the first coordinate and the x variable of the second coordinate.  For example;

(3,6)  (7,4)       x(1)=3, y(1)=6
                      x(2)=7, y(2)=4

6-4=2
3-7=-4

m=-(1/2)

Now that you have slope, you can use one of the given coordinates and plug the x and y in the slope-intercept form equation, to find the y-intercept(b). For example using the coordinate (3,6);

y=-(1/2)x+b
6=-(1/2)(3)+b
b=15/2 (or 7.5)

Now you have the equation of the line in slope-intercept form:
y=-(1/2)x+15/2

As for 1b. I really don't understand your question, but if you want to clarify I'd be glad to help!

Hope this helps! Let me know if it's clear or not

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