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Home Q & A Board Laboratory Help Introductory Courses
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obehmardi obehmardi
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11 years ago
During lab, students mixed two solutions of soluble ions in a ceramic well to determine if a precipitate forms. Based on extrapolation of your lab results, write the dissolution reaction for the ionic solids below. (Use the lowest possible coefficients. Include states-of-matter under the given conditions in your answer.)

Cu(ClO4)2
Li3PO4

An explanation would be great. Thanks for any help!
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#1
11 years ago
There are two possible new compounds that could form from mixing these two solutions:

3Cu2+(aq) + 2PO43- (aq) ---> Cu3(PO4)2     copper phosphate

Li+ + ClO4- ---> LiClO4    lithium perchlorate

If a precipitate formed, you need to ask youself which of these products is insoluble in water.  Wikipedia tells us that lithium perchlorate is soluble in water but  that copper phosphate is not, so copper phosphate is your precipitate! It should have been blue or green http://en.wikipedia.org/wiki/Copper_phosphate

So the reaction is:
3Cu2+(aq) + 2PO43- (aq) ---> Cu3(PO4)2 (s)
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