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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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Lilyshine Lilyshine
wrote...
12 years ago
What is acid dissociation constant and percent ionization for 1.0 M formic acid pH 1.88?
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wrote...
#1
12 years ago
Im english and dont understand this. Try putting it in simpler terms or chemical terms if you can.
sodaxcandy08 Author
wrote...
#2
12 years ago
[H+]= 10^-1.88=0.0132 M

HCOOH <=> H+ + HCOO-

at equilibrium [H+]= [HCOO-] = 0.0132 M
[HCOOH]= 1.0 - 0.0132=0.987 M

Ka = [H+][HCOO-]/ [HCOOH] = (0.0132)(0.0132)/ 0.987 =1.77 x 10^-4

% ionization = 0.0132 x 100/ 1.0 = 1.32%
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