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11 years ago
What are the equilibrium concentrations of hydronium ion, acetate ion, and acetic acid in a 0.20 M aqueous solution of acetic acid?  What is the pH of the solution?  Ka = 1.8 x 10-5
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#1
11 years ago
CH3COOH Leftwards Arrow--> CH3COO- + H+
initial concentration
0.20
change
-x. . . . . . .. . . .. . . .+x .. . . . . .+x
at equilibrium
0.20-x. . . . . .. . . . . .x .. . . . . . ..x
1.8 x 10^-5 = x^2 / 0.20-x

x = [CH3COO-]= [H+]= 1.9 x 10^- 3 M
[CH3COOH]= 0.20 - 1.9 x 10^-3 =  0.198 M ( 0.20 with 2 significant figures)
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