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Julia Julia
wrote...
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12 years ago
I know how to calculate it with (M) but it wants me to use my acid base chart and I'm so confused please help me with this I have a test tomorrow!!  If you could explain this to me and/or provide me an example to follow!

Thanks so much!!!
also I am not given pH so I can't work with that.  but Thanks a lot miroku!
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wrote...
12 years ago
For example you have

H2O + HCl <=> H2Cl+ + OH-

K = [H2Cl+][OH-]/[HCl]

You are not given M but you are given pH
You can use the pH to find OH-.
pH + pOH = 14

Once you have OH-, you know that
one mole of OH- equal to one mole of H2Cl+
we are just using stoichiometry from the equation.
just divide the mole by the given liter to find M

To find HCl, we also know that when x mole of HCl
reacts with H2O, x mole of OH- and x mole of H2Cl+ is generated.

That is to say, the amount of HCl lost = amount of OH- gain = amount of H2Cl+ gain = stoichiometry

Plug everything you know in the equil. equation and you will get K.

The trick is stoichiometry, converting pH to pOH, and understanding what is lost and gain.

Good luck with your test
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