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jules_78 jules_78
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11 years ago
In a population that is in Hardy Weinberg equilibrium for two alleses, C and c, 16% of the population show a recessive trait. Assuming C is dominant to c, what would be the frequency of the heterozygotes in the population?
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wrote...
11 years ago
16% = 0.16 = q^2.
So, q = 0.4
Since p + q =1 p = 0.6.

Heterozygote frequency = 2pq = 2 x 0.6 x 0.4 = 0.48 = 48%.
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