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Fire_Fly Fire_Fly
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11 years ago
how would i do a hetero-cross with out the huge punnet square of Aa+Bb+Qq
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wrote...
11 years ago
3 pairs of alleles = 2^3 = 8 gametes.
8 x 8 gives 64 possibilities.

ABQ with each of all 8 =8 eg AABBQQ,AABBQq,...
ABq with each of all 8 = 8
AbQ with each of all 8 = 8
Abq with each of all 8 = 8
aBQ with each of all 8 = 8
aBq with each of all 8 = 8
abQ with each of all 8 = 8
abq with each of all 8 = 8 eg.AaBbQq,.......
wrote...
11 years ago
It is really easiest to see on a Punnet square - take a look at this web site, which has one:
http://www.science.oregonstate.edu/bi10x/otherresources/punnett%20squares.htm
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