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Home Q & A Board Biology-Related Homework Help Genetics and Developmental Biology
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rkkovach rkkovach
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11 years ago
Question:
Suppose an animal is heterozygous AaBb, and the traits are not linked. When meiosis occurs, what is the total number of possible combinations of gametes that can be made for these traits?

I need to know the answer for a study guide due tomorrow.
Help will be much appreciated!
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#1
11 years ago
No problem. What you do is to match the first gene, A, with each of the two possible unrelated alleles, and then you do the same for the a allele.
The possibilities represent the different possibilities in the gametes made by this individual for these two traits.
Doing this we get:

AB, Ab, aB, ab

So this individual is capable of making four sperm or four eggs (gametes) with one of these 4 gene combinations in each.
wrote...
#2
11 years ago
There are 4 possibilities.  They are:
AB, Ab, aB and ab

The way to figure this out in case many more letters/alleles are thrown your way is to look at it like this:

There are 2 possibilities for the A's  (A or a), and there are 2 possibilities for the B's (B or b).
Multiply the possibilities:  2 x 2 which equals 4, which is the answer.
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